Base | Representation |
---|---|
bin | 1011101001111101111… |
… | …0001111101000010101 |
3 | 201010212100102020100122 |
4 | 2322133132033220111 |
5 | 11240044431020201 |
6 | 231554003521325 |
7 | 20316142633031 |
oct | 2723736175025 |
9 | 633770366318 |
10 | 200244001301 |
11 | 77a17577a73 |
12 | 32985389245 |
13 | 15b62a41346 |
14 | 99986791c1 |
15 | 531eac0e1b |
hex | 2e9f78fa15 |
200244001301 has 4 divisors (see below), whose sum is σ = 200281554732. Its totient is φ = 200206447872.
The previous prime is 200244001267. The next prime is 200244001313. The reversal of 200244001301 is 103100442002.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 103100442002 = 2 ⋅51550221001.
It can be written as a sum of positive squares in 2 ways, for example, as 116260540900 + 83983460401 = 340970^2 + 289799^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200244001301 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 200244001301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200244001381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18768716 + ... + 18779381.
It is an arithmetic number, because the mean of its divisors is an integer number (50070388683).
Almost surely, 2200244001301 is an apocalyptic number.
It is an amenable number.
200244001301 is a deficient number, since it is larger than the sum of its proper divisors (37553431).
200244001301 is an equidigital number, since it uses as much as digits as its factorization.
200244001301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37553430.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 200244001301 its reverse (103100442002), we get a palindrome (303344443303).
The spelling of 200244001301 in words is "two hundred billion, two hundred forty-four million, one thousand, three hundred one".
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