Base | Representation |
---|---|
bin | 11101001001011101010… |
… | …100001000110110000011 |
3 | 21002111010221010000021122 |
4 | 131021131110020312003 |
5 | 230304141200221011 |
6 | 4132101432542455 |
7 | 264466465542065 |
oct | 35113524106603 |
9 | 7074127100248 |
10 | 2003020320131 |
11 | 702526830026 |
12 | 284247551a2b |
13 | 116b6521194c |
14 | 6cd37a65735 |
15 | 371832373db |
hex | 1d25d508d83 |
2003020320131 has 2 divisors, whose sum is σ = 2003020320132. Its totient is φ = 2003020320130.
The previous prime is 2003020320073. The next prime is 2003020320143. The reversal of 2003020320131 is 1310230203002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003020320131 - 234 = 1985840450947 is a prime.
It is a super-2 number, since 2×20030203201312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2003020320181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001510160065 + 1001510160066.
It is an arithmetic number, because the mean of its divisors is an integer number (1001510160066).
Almost surely, 22003020320131 is an apocalyptic number.
2003020320131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003020320131 is an equidigital number, since it uses as much as digits as its factorization.
2003020320131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 2003020320131 its reverse (1310230203002), we get a palindrome (3313250523133).
The spelling of 2003020320131 in words is "two trillion, three billion, twenty million, three hundred twenty thousand, one hundred thirty-one".
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