Base | Representation |
---|---|
bin | 1001000110111101001011… |
… | …00111001101100101001011 |
3 | 2121220212110211211101121022 |
4 | 10203132211213031211023 |
5 | 10111133333010134011 |
6 | 110333430225103055 |
7 | 4135064205326453 |
oct | 443364547154513 |
9 | 77825424741538 |
10 | 20030211021131 |
11 | 6422845a313a3 |
12 | 22b5ba5187a8b |
13 | b23ac12c16bc |
14 | 4d3678716d63 |
15 | 24b0722948db |
hex | 1237a59cd94b |
20030211021131 has 2 divisors, whose sum is σ = 20030211021132. Its totient is φ = 20030211021130.
The previous prime is 20030211021113. The next prime is 20030211021179. The reversal of 20030211021131 is 13112011203002.
Together with previous prime (20030211021113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20030211021131 - 226 = 20030143912267 is a prime.
It is a super-2 number, since 2×200302110211312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20030211027131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015105510565 + 10015105510566.
It is an arithmetic number, because the mean of its divisors is an integer number (10015105510566).
Almost surely, 220030211021131 is an apocalyptic number.
20030211021131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20030211021131 is an equidigital number, since it uses as much as digits as its factorization.
20030211021131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20030211021131 its reverse (13112011203002), we get a palindrome (33142222224133).
The spelling of 20030211021131 in words is "twenty trillion, thirty billion, two hundred eleven million, twenty-one thousand, one hundred thirty-one".
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