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20030212230120 = 23325611516040547
BaseRepresentation
bin1001000110111101001011…
…01011110100101111101000
32121220212110221002211000200
410203132211223310233220
510111133333312330440
6110333430311032200
74135064221523301
oct443364553645750
977825427084020
1020030212230120
116422846687764
1222b5ba566b660
13b23ac1625a91
144d367894d7a8
1524b072432c30
hex1237a5af4be8

20030212230120 has 192 divisors, whose sum is σ = 66603565491840. Its totient is φ = 5219031744000.

The previous prime is 20030212230113. The next prime is 20030212230167. The reversal of 20030212230120 is 2103221203002.

20030212230120 is a `hidden beast` number, since 2 + 0 + 0 + 302 + 12 + 230 + 120 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 20030212230093 and 20030212230102.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 295687 + ... + 6336233.

It is an arithmetic number, because the mean of its divisors is an integer number (346893570270).

Almost surely, 220030212230120 is an apocalyptic number.

20030212230120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20030212230120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33301782745920).

20030212230120 is an abundant number, since it is smaller than the sum of its proper divisors (46573353261720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20030212230120 is a wasteful number, since it uses less digits than its factorization.

20030212230120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6040776 (or 6040769 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 20030212230120 its reverse (2103221203002), we get a palindrome (22133433433122).

The spelling of 20030212230120 in words is "twenty trillion, thirty billion, two hundred twelve million, two hundred thirty thousand, one hundred twenty".