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2003031330109 = 2837077849223
BaseRepresentation
bin11101001001011101111…
…110001000110100111101
321002111011200211101010121
4131021131332020310331
5230304202010030414
64132102504534541
7264466661246125
oct35113576106475
97074150741117
102003031330109
11702531a6aa87
1228424b181451
13116b67598124
146cd392cdc85
15371841ae724
hex1d25df88d3d

2003031330109 has 4 divisors (see below), whose sum is σ = 2010109179616. Its totient is φ = 1995953480604.

The previous prime is 2003031330043. The next prime is 2003031330127. The reversal of 2003031330109 is 9010331303002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003031330109 - 225 = 2002997775677 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003031330149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3538924329 + ... + 3538924894.

It is an arithmetic number, because the mean of its divisors is an integer number (502527294904).

Almost surely, 22003031330109 is an apocalyptic number.

It is an amenable number.

2003031330109 is a deficient number, since it is larger than the sum of its proper divisors (7077849507).

2003031330109 is an equidigital number, since it uses as much as digits as its factorization.

2003031330109 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7077849506.

The product of its (nonzero) digits is 1458, while the sum is 25.

The spelling of 2003031330109 in words is "two trillion, three billion, thirty-one million, three hundred thirty thousand, one hundred nine".

Divisors: 1 283 7077849223 2003031330109