Base | Representation |
---|---|
bin | 101101100010110100000000… |
… | …110100011110100111100111 |
3 | 222021012220200021121010012110 |
4 | 231202310000310132213213 |
5 | 202223241404301243310 |
6 | 1550002323405452103 |
7 | 60122341563602424 |
oct | 5542640064364747 |
9 | 867186607533173 |
10 | 200304403540455 |
11 | 58906690967785 |
12 | 1a570403571033 |
13 | 879c8164c0116 |
14 | 3766adb922d4b |
15 | 182559d135d20 |
hex | b62d00d1e9e7 |
200304403540455 has 32 divisors (see below), whose sum is σ = 337355867197440. Its totient is φ = 101206110787200.
The previous prime is 200304403540453. The next prime is 200304403540471. The reversal of 200304403540455 is 554045304403002.
200304403540455 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 200304403540455 - 21 = 200304403540453 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200304403540453) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 105539130 + ... + 107420280.
It is an arithmetic number, because the mean of its divisors is an integer number (10542370849920).
Almost surely, 2200304403540455 is an apocalyptic number.
200304403540455 is a deficient number, since it is larger than the sum of its proper divisors (137051463656985).
200304403540455 is a wasteful number, since it uses less digits than its factorization.
200304403540455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2254791.
The product of its (nonzero) digits is 576000, while the sum is 39.
Adding to 200304403540455 its reverse (554045304403002), we get a palindrome (754349707943457).
The spelling of 200304403540455 in words is "two hundred trillion, three hundred four billion, four hundred three million, five hundred forty thousand, four hundred fifty-five".
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