Base | Representation |
---|---|
bin | 11101001001100010000… |
… | …101010100000110000011 |
3 | 21002111100111122102122121 |
4 | 131021202011110012003 |
5 | 230304322140221011 |
6 | 4132113411345111 |
7 | 264501456535201 |
oct | 35114205240603 |
9 | 7074314572577 |
10 | 2003100320131 |
11 | 702567a01229 |
12 | 28426a2b2197 |
13 | 116b78972021 |
14 | 6cd4452c071 |
15 | 3718a28ae71 |
hex | 1d262154183 |
2003100320131 has 2 divisors, whose sum is σ = 2003100320132. Its totient is φ = 2003100320130.
The previous prime is 2003100320119. The next prime is 2003100320159. The reversal of 2003100320131 is 1310230013002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003100320131 - 213 = 2003100311939 is a prime.
It is a super-2 number, since 2×20031003201312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2003100320171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001550160065 + 1001550160066.
It is an arithmetic number, because the mean of its divisors is an integer number (1001550160066).
Almost surely, 22003100320131 is an apocalyptic number.
2003100320131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003100320131 is an equidigital number, since it uses as much as digits as its factorization.
2003100320131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 2003100320131 its reverse (1310230013002), we get a palindrome (3313330333133).
The spelling of 2003100320131 in words is "two trillion, three billion, one hundred million, three hundred twenty thousand, one hundred thirty-one".
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