Base | Representation |
---|---|
bin | 1001000110111110101110… |
… | …01011010000011000000111 |
3 | 2121220221121210111121100221 |
4 | 10203133113023100120013 |
5 | 10111142033343201401 |
6 | 110334044531445211 |
7 | 4135123623252604 |
oct | 443372713203007 |
9 | 77827553447327 |
10 | 20031042553351 |
11 | 6423132349905 |
12 | 22b6197756807 |
13 | b23bc4664abb |
14 | 4d3716d2d6ab |
15 | 24b0c02997a1 |
hex | 1237d72d0607 |
20031042553351 has 4 divisors (see below), whose sum is σ = 20031051772600. Its totient is φ = 20031033334104.
The previous prime is 20031042553331. The next prime is 20031042553411. The reversal of 20031042553351 is 15335524013002.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 20031042553351 - 213 = 20031042545159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20031042553331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 649645 + ... + 6362713.
It is an arithmetic number, because the mean of its divisors is an integer number (5007762943150).
Almost surely, 220031042553351 is an apocalyptic number.
20031042553351 is a deficient number, since it is larger than the sum of its proper divisors (9219249).
20031042553351 is an equidigital number, since it uses as much as digits as its factorization.
20031042553351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9219248.
The product of its (nonzero) digits is 54000, while the sum is 34.
Adding to 20031042553351 its reverse (15335524013002), we get a palindrome (35366566566353).
The spelling of 20031042553351 in words is "twenty trillion, thirty-one billion, forty-two million, five hundred fifty-three thousand, three hundred fifty-one".
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