Base | Representation |
---|---|
bin | 11101001001100010101… |
… | …010010010000100111001 |
3 | 21002111101011212210021211 |
4 | 131021202222102010321 |
5 | 230304332130324233 |
6 | 4132114355203121 |
7 | 264501635110054 |
oct | 35114252220471 |
9 | 7074334783254 |
10 | 2003110011193 |
11 | 702572420275 |
12 | 2842715a64a1 |
13 | 116b7a986095 |
14 | 6cd45931a9b |
15 | 3718b0525cd |
hex | 1d262a92139 |
2003110011193 has 2 divisors, whose sum is σ = 2003110011194. Its totient is φ = 2003110011192.
The previous prime is 2003110011173. The next prime is 2003110011307. The reversal of 2003110011193 is 3911100113002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1042059180969 + 961050830224 = 1020813^2 + 980332^2 .
It is a cyclic number.
It is not a de Polignac number, because 2003110011193 - 225 = 2003076456761 is a prime.
It is not a weakly prime, because it can be changed into another prime (2003110011173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001555005596 + 1001555005597.
It is an arithmetic number, because the mean of its divisors is an integer number (1001555005597).
Almost surely, 22003110011193 is an apocalyptic number.
It is an amenable number.
2003110011193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003110011193 is an equidigital number, since it uses as much as digits as its factorization.
2003110011193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 22.
Adding to 2003110011193 its reverse (3911100113002), we get a palindrome (5914210124195).
The spelling of 2003110011193 in words is "two trillion, three billion, one hundred ten million, eleven thousand, one hundred ninety-three".
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