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2003110011211 = 4014995286811
BaseRepresentation
bin11101001001100010101…
…010010010000101001011
321002111101011212210022111
4131021202222102011023
5230304332130324321
64132114355203151
7264501635110111
oct35114252220513
97074334783274
102003110011211
11702572420291
122842715a64b7
13116b7a9860aa
146cd45931ab1
153718b0525e1
hex1d262a9214b

2003110011211 has 4 divisors (see below), whose sum is σ = 2008105298424. Its totient is φ = 1998114724000.

The previous prime is 2003110011193. The next prime is 2003110011307. The reversal of 2003110011211 is 1121100113002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003110011211 - 225 = 2003076456779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003110011191 and 2003110011200.

It is not an unprimeable number, because it can be changed into a prime (2003110011011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2497643005 + ... + 2497643806.

It is an arithmetic number, because the mean of its divisors is an integer number (502026324606).

Almost surely, 22003110011211 is an apocalyptic number.

2003110011211 is a deficient number, since it is larger than the sum of its proper divisors (4995287213).

2003110011211 is an equidigital number, since it uses as much as digits as its factorization.

2003110011211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4995287212.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 2003110011211 its reverse (1121100113002), we get a palindrome (3124210124213).

The spelling of 2003110011211 in words is "two trillion, three billion, one hundred ten million, eleven thousand, two hundred eleven".

Divisors: 1 401 4995286811 2003110011211