Base | Representation |
---|---|
bin | 11101001001100010110… |
… | …010010010100100010001 |
3 | 21002111101022211102210111 |
4 | 131021202302102210101 |
5 | 230304333200012403 |
6 | 4132114512201321 |
7 | 264501662002054 |
oct | 35114262224421 |
9 | 7074338742714 |
10 | 2003112110353 |
11 | 702573624412 |
12 | 284272239241 |
13 | 116b7b23c6a3 |
14 | 6cd45d1aa9b |
15 | 3718b31956d |
hex | 1d262c92911 |
2003112110353 has 2 divisors, whose sum is σ = 2003112110354. Its totient is φ = 2003112110352.
The previous prime is 2003112110317. The next prime is 2003112110369. The reversal of 2003112110353 is 3530112113002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1417225963729 + 585886146624 = 1190473^2 + 765432^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003112110353 is a prime.
It is not a weakly prime, because it can be changed into another prime (2003112110393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001556055176 + 1001556055177.
It is an arithmetic number, because the mean of its divisors is an integer number (1001556055177).
Almost surely, 22003112110353 is an apocalyptic number.
It is an amenable number.
2003112110353 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003112110353 is an equidigital number, since it uses as much as digits as its factorization.
2003112110353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 2003112110353 its reverse (3530112113002), we get a palindrome (5533224223355).
The spelling of 2003112110353 in words is "two trillion, three billion, one hundred twelve million, one hundred ten thousand, three hundred fifty-three".
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