Base | Representation |
---|---|
bin | 11101001001100010110… |
… | …101101110001101101111 |
3 | 21002111101101112010220220 |
4 | 131021202311232031233 |
5 | 230304333412310111 |
6 | 4132114543342423 |
7 | 264502002440040 |
oct | 35114265561557 |
9 | 7074341463826 |
10 | 2003113010031 |
11 | 702574089351 |
12 | 2842725b1a13 |
13 | 116b7b496043 |
14 | 6cd460b28c7 |
15 | 3718b445e06 |
hex | 1d262d6e36f |
2003113010031 has 32 divisors (see below), whose sum is σ = 3094883117568. Its totient is φ = 1128698012160.
The previous prime is 2003113009999. The next prime is 2003113010047. The reversal of 2003113010031 is 1300103113002.
It is not a de Polignac number, because 2003113010031 - 25 = 2003113009999 is a prime.
It is a super-2 number, since 2×20031130100312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003113012031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6660940 + ... + 6955166.
It is an arithmetic number, because the mean of its divisors is an integer number (96715097424).
Almost surely, 22003113010031 is an apocalyptic number.
2003113010031 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2003113010031 is a deficient number, since it is larger than the sum of its proper divisors (1091770107537).
2003113010031 is a wasteful number, since it uses less digits than its factorization.
2003113010031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298751.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 2003113010031 its reverse (1300103113002), we get a palindrome (3303216123033).
The spelling of 2003113010031 in words is "two trillion, three billion, one hundred thirteen million, ten thousand, thirty-one".
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