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200311314132399 = 366770438044133
BaseRepresentation
bin101101100010111010011100…
…101110010010110110101111
3222021020120111220002120012020
4231202322130232102312233
5202223400032404214044
61550005425231441223
760123005045633001
oct5542723456226657
9867216456076166
10200311314132399
11589096077a4798
121a571811986213
1387a0378120692
143767195648371
151825854b8da19
hexb62e9cb92daf

200311314132399 has 4 divisors (see below), whose sum is σ = 267081752176536. Its totient is φ = 133540876088264.

The previous prime is 200311314132337. The next prime is 200311314132421. The reversal of 200311314132399 is 993231413113002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200311314132399 - 27 = 200311314132271 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200311314132399.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200311314132799) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33385219022064 + ... + 33385219022069.

It is an arithmetic number, because the mean of its divisors is an integer number (66770438044134).

Almost surely, 2200311314132399 is an apocalyptic number.

200311314132399 is a deficient number, since it is larger than the sum of its proper divisors (66770438044137).

200311314132399 is an equidigital number, since it uses as much as digits as its factorization.

200311314132399 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66770438044136.

The product of its (nonzero) digits is 104976, while the sum is 42.

The spelling of 200311314132399 in words is "two hundred trillion, three hundred eleven billion, three hundred fourteen million, one hundred thirty-two thousand, three hundred ninety-nine".

Divisors: 1 3 66770438044133 200311314132399