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200311314132521 is a prime number
BaseRepresentation
bin101101100010111010011100…
…101110010010111000101001
3222021020120111220002120100202
4231202322130232102320221
5202223400032404220041
61550005425231441545
760123005045633234
oct5542723456227051
9867216456076322
10200311314132521
11589096077a4899
121a5718119862b5
1387a0378120757
14376719564841b
151825854b8da9b
hexb62e9cb92e29

200311314132521 has 2 divisors, whose sum is σ = 200311314132522. Its totient is φ = 200311314132520.

The previous prime is 200311314132437. The next prime is 200311314132547. The reversal of 200311314132521 is 125231413113002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196095519634921 + 4215794497600 = 14003411^2 + 2053240^2 .

It is a cyclic number.

It is not a de Polignac number, because 200311314132521 - 242 = 195913267621417 is a prime.

It is not a weakly prime, because it can be changed into another prime (200311314132421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100155657066260 + 100155657066261.

It is an arithmetic number, because the mean of its divisors is an integer number (100155657066261).

Almost surely, 2200311314132521 is an apocalyptic number.

It is an amenable number.

200311314132521 is a deficient number, since it is larger than the sum of its proper divisors (1).

200311314132521 is an equidigital number, since it uses as much as digits as its factorization.

200311314132521 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 200311314132521 its reverse (125231413113002), we get a palindrome (325542727245523).

The spelling of 200311314132521 in words is "two hundred trillion, three hundred eleven billion, three hundred fourteen million, one hundred thirty-two thousand, five hundred twenty-one".