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2003114483 is a prime number
BaseRepresentation
bin111011101100101…
…0001100111110011
312011121012202111022
41313121101213303
513100244130413
6530433410055
7100432122626
oct16731214763
95147182438
102003114483
11938784617
1247aa0992b
1325bcc7b56
14150069dbd
15bacca608
hex776519f3

2003114483 has 2 divisors, whose sum is σ = 2003114484. Its totient is φ = 2003114482.

The previous prime is 2003114461. The next prime is 2003114543. The reversal of 2003114483 is 3844113002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2003114483 - 28 = 2003114227 is a prime.

It is not a weakly prime, because it can be changed into another prime (2003114783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001557241 + 1001557242.

It is an arithmetic number, because the mean of its divisors is an integer number (1001557242).

Almost surely, 22003114483 is an apocalyptic number.

2003114483 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003114483 is an equidigital number, since it uses as much as digits as its factorization.

2003114483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

The square root of 2003114483 is about 44756.1669828863. The cubic root of 2003114483 is about 1260.5747111579.

Adding to 2003114483 its reverse (3844113002), we get a palindrome (5847227485).

The spelling of 2003114483 in words is "two billion, three million, one hundred fourteen thousand, four hundred eighty-three".