Base | Representation |
---|---|
bin | 101101100010111011000101… |
… | …101011101000111100110011 |
3 | 222021020122021210010102010011 |
4 | 231202323011223220330303 |
5 | 202223402434313133243 |
6 | 1550010021340115351 |
7 | 60123031061526601 |
oct | 5542730553507463 |
9 | 867218253112104 |
10 | 200312001302323 |
11 | 5890992a680719 |
12 | 1a571983b35b57 |
13 | 87a04575b9cc1 |
14 | 376721ca02871 |
15 | 182589517989d |
hex | b62ec5ae8f33 |
200312001302323 has 2 divisors, whose sum is σ = 200312001302324. Its totient is φ = 200312001302322.
The previous prime is 200312001302213. The next prime is 200312001302339. The reversal of 200312001302323 is 323203100213002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200312001302323 - 217 = 200312001171251 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200312001302294 and 200312001302303.
It is not a weakly prime, because it can be changed into another prime (200312001302353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156000651161 + 100156000651162.
It is an arithmetic number, because the mean of its divisors is an integer number (100156000651162).
Almost surely, 2200312001302323 is an apocalyptic number.
200312001302323 is a deficient number, since it is larger than the sum of its proper divisors (1).
200312001302323 is an equidigital number, since it uses as much as digits as its factorization.
200312001302323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 200312001302323 its reverse (323203100213002), we get a palindrome (523515101515325).
The spelling of 200312001302323 in words is "two hundred trillion, three hundred twelve billion, one million, three hundred two thousand, three hundred twenty-three".
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