Search a number
-
+
200312140000099 is a prime number
BaseRepresentation
bin101101100010111011001101…
…111100101110101101100011
3222021020122122110002222200211
4231202323031330232231203
5202223403230320000344
61550010043212554551
760123034364454361
oct5542731574565543
9867218573088624
10200312140000099
11589099a09a3386
121a571a02482a57
1387a047a25c6aa
1437672331c8631
1518258a2425334
hexb62ecdf2eb63

200312140000099 has 2 divisors, whose sum is σ = 200312140000100. Its totient is φ = 200312140000098.

The previous prime is 200312140000043. The next prime is 200312140000103. The reversal of 200312140000099 is 990000041213002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 200312140000099 - 27 = 200312139999971 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200312140000099.

It is not a weakly prime, because it can be changed into another prime (200312140090099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100156070000049 + 100156070000050.

It is an arithmetic number, because the mean of its divisors is an integer number (100156070000050).

Almost surely, 2200312140000099 is an apocalyptic number.

200312140000099 is a deficient number, since it is larger than the sum of its proper divisors (1).

200312140000099 is an equidigital number, since it uses as much as digits as its factorization.

200312140000099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 200312140000099 in words is "two hundred trillion, three hundred twelve billion, one hundred forty million, ninety-nine", and thus it is an aban number.