Base | Representation |
---|---|
bin | 1001000110111111011011… |
… | …10111110100010010101001 |
3 | 2121220222121100000020121002 |
4 | 10203133231313310102221 |
5 | 10111143323333133140 |
6 | 110334150413124345 |
7 | 4135136225655131 |
oct | 443375567642251 |
9 | 77828540006532 |
10 | 20031423333545 |
11 | 6423308287688 |
12 | 22b62831896b5 |
13 | b23c55507120 |
14 | 4d375172dac1 |
15 | 24b0e3913415 |
hex | 1237eddf44a9 |
20031423333545 has 16 divisors (see below), whose sum is σ = 25968424199760. Its totient is φ = 14745771842304.
The previous prime is 20031423333529. The next prime is 20031423333553. The reversal of 20031423333545 is 54533332413002.
It can be written as a sum of positive squares in 8 ways, for example, as 10056052792384 + 9975370541161 = 3171128^2 + 3158381^2 .
It is a cyclic number.
It is not a de Polignac number, because 20031423333545 - 24 = 20031423333529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20031423333499 and 20031423333508.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 486061010 + ... + 486102219.
It is an arithmetic number, because the mean of its divisors is an integer number (1623026512485).
Almost surely, 220031423333545 is an apocalyptic number.
It is an amenable number.
20031423333545 is a deficient number, since it is larger than the sum of its proper divisors (5937000866215).
20031423333545 is a wasteful number, since it uses less digits than its factorization.
20031423333545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 972163564.
The product of its (nonzero) digits is 388800, while the sum is 38.
Adding to 20031423333545 its reverse (54533332413002), we get a palindrome (74564755746547).
The spelling of 20031423333545 in words is "twenty trillion, thirty-one billion, four hundred twenty-three million, three hundred thirty-three thousand, five hundred forty-five".
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