Base | Representation |
---|---|
bin | 10010101010000000… |
… | …011011110110111011 |
3 | 1220201001221121220102 |
4 | 102222000123312323 |
5 | 312011210010021 |
6 | 13111433350015 |
7 | 1306262061044 |
oct | 225200336673 |
9 | 56631847812 |
10 | 20032110011 |
11 | 854a670821 |
12 | 3a7086830b |
13 | 1b7323b144 |
14 | d806838cb |
15 | 7c39b000b |
hex | 4aa01bdbb |
20032110011 has 4 divisors (see below), whose sum is σ = 20088858552. Its totient is φ = 19975361472.
The previous prime is 20032109983. The next prime is 20032110053. The reversal of 20032110011 is 11001123002.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11001123002 = 2 ⋅5500561501.
It is a cyclic number.
It is not a de Polignac number, because 20032110011 - 26 = 20032109947 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20032109974 and 20032110001.
It is not an unprimeable number, because it can be changed into a prime (20032110071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28373741 + ... + 28374446.
It is an arithmetic number, because the mean of its divisors is an integer number (5022214638).
Almost surely, 220032110011 is an apocalyptic number.
20032110011 is a deficient number, since it is larger than the sum of its proper divisors (56748541).
20032110011 is an equidigital number, since it uses as much as digits as its factorization.
20032110011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56748540.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 20032110011 its reverse (11001123002), we get a palindrome (31033233013).
The spelling of 20032110011 in words is "twenty billion, thirty-two million, one hundred ten thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •