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2003213200103 = 4761216963169
BaseRepresentation
bin11101001001101000110…
…011111010101011100111
321002111122101001022212022
4131021220303322223213
5230310040034400403
64132132523013355
7264504330153263
oct35115063725347
97074571038768
102003213200103
1170261569a665
122842a006a25b
13116b961751cb
146cd555130a3
1537195136d38
hex1d268cfaae7

2003213200103 has 8 divisors (see below), whose sum is σ = 2046169283520. Its totient is φ = 1960271055360.

The previous prime is 2003213200073. The next prime is 2003213200117. The reversal of 2003213200103 is 3010023123002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2003213200103 - 26 = 2003213200039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003213200123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3193898 + ... + 3769271.

It is an arithmetic number, because the mean of its divisors is an integer number (255771160440).

Almost surely, 22003213200103 is an apocalyptic number.

2003213200103 is a deficient number, since it is larger than the sum of its proper divisors (42956083417).

2003213200103 is an equidigital number, since it uses as much as digits as its factorization.

2003213200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6969337.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 2003213200103 its reverse (3010023123002), we get a palindrome (5013236323105).

The spelling of 2003213200103 in words is "two trillion, three billion, two hundred thirteen million, two hundred thousand, one hundred three".

Divisors: 1 47 6121 287687 6963169 327268943 42621557449 2003213200103