Base | Representation |
---|---|
bin | 101101100011000101101101… |
… | …010101111111001101000011 |
3 | 222021021201201110120020102012 |
4 | 231203011231111333031003 |
5 | 202224044312424230222 |
6 | 1550015145034243135 |
7 | 60123613462144466 |
oct | 5543055525771503 |
9 | 867251643506365 |
10 | 200323404133187 |
11 | 58913751238285 |
12 | 1a5740268864ab |
13 | 87a1553b075ba |
14 | 37679c11b32dd |
15 | 1825d1128b1e2 |
hex | b6316d57f343 |
200323404133187 has 2 divisors, whose sum is σ = 200323404133188. Its totient is φ = 200323404133186.
The previous prime is 200323404133159. The next prime is 200323404133271. The reversal of 200323404133187 is 781331404323002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200323404133187 - 26 = 200323404133123 is a prime.
It is a super-4 number, since 4×2003234041331874 (a number of 58 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (200323404133157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100161702066593 + 100161702066594.
It is an arithmetic number, because the mean of its divisors is an integer number (100161702066594).
Almost surely, 2200323404133187 is an apocalyptic number.
200323404133187 is a deficient number, since it is larger than the sum of its proper divisors (1).
200323404133187 is an equidigital number, since it uses as much as digits as its factorization.
200323404133187 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 290304, while the sum is 41.
Adding to 200323404133187 its reverse (781331404323002), we get a palindrome (981654808456189).
The spelling of 200323404133187 in words is "two hundred trillion, three hundred twenty-three billion, four hundred four million, one hundred thirty-three thousand, one hundred eighty-seven".
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