Base | Representation |
---|---|
bin | 10010101010000001… |
… | …100101001000000001 |
3 | 1220201002111212120022 |
4 | 102222001211020001 |
5 | 312011244110423 |
6 | 13111444023225 |
7 | 1306264451012 |
oct | 225201451001 |
9 | 56632455508 |
10 | 20032410113 |
11 | 854a856241 |
12 | 3a70991b15 |
13 | 1b73314911 |
14 | d80721009 |
15 | 7c3a1ddc8 |
hex | 4aa065201 |
20032410113 has 2 divisors, whose sum is σ = 20032410114. Its totient is φ = 20032410112.
The previous prime is 20032410109. The next prime is 20032410217. The reversal of 20032410113 is 31101423002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16913522704 + 3118887409 = 130052^2 + 55847^2 .
It is a cyclic number.
It is not a de Polignac number, because 20032410113 - 22 = 20032410109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20032410091 and 20032410100.
It is not a weakly prime, because it can be changed into another prime (20032460113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016205056 + 10016205057.
It is an arithmetic number, because the mean of its divisors is an integer number (10016205057).
Almost surely, 220032410113 is an apocalyptic number.
It is an amenable number.
20032410113 is a deficient number, since it is larger than the sum of its proper divisors (1).
20032410113 is an equidigital number, since it uses as much as digits as its factorization.
20032410113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 20032410113 its reverse (31101423002), we get a palindrome (51133833115).
The spelling of 20032410113 in words is "twenty billion, thirty-two million, four hundred ten thousand, one hundred thirteen".
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