Base | Representation |
---|---|
bin | 1001000111000001100100… |
… | …01111111011011110100101 |
3 | 2121221002120021121121011101 |
4 | 10203200302033323132211 |
5 | 10111203201022131000 |
6 | 110334500313040101 |
7 | 4135206525525523 |
oct | 443406217733645 |
9 | 77832507547141 |
10 | 20032570505125 |
11 | 6423846890672 |
12 | 22b65433b6031 |
13 | b240a9092989 |
14 | 4d381dc2b313 |
15 | 24b15e4b5e6a |
hex | 1238323fb7a5 |
20032570505125 has 16 divisors (see below), whose sum is σ = 25038933923952. Its totient is φ = 16001514139200.
The previous prime is 20032570505099. The next prime is 20032570505173. The reversal of 20032570505125 is 52150507523002.
It can be written as a sum of positive squares in 8 ways, for example, as 4333216763044 + 15699353742081 = 2081638^2 + 3962241^2 .
It is not a de Polignac number, because 20032570505125 - 237 = 19895131551653 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 122629374 + ... + 122792623.
It is an arithmetic number, because the mean of its divisors is an integer number (1564933370247).
Almost surely, 220032570505125 is an apocalyptic number.
20032570505125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20032570505125 is a deficient number, since it is larger than the sum of its proper divisors (5006363418827).
20032570505125 is an equidigital number, since it uses as much as digits as its factorization.
20032570505125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245422665 (or 245422655 counting only the distinct ones).
The product of its (nonzero) digits is 105000, while the sum is 37.
The spelling of 20032570505125 in words is "twenty trillion, thirty-two billion, five hundred seventy million, five hundred five thousand, one hundred twenty-five".
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