Base | Representation |
---|---|
bin | 101101100011001101110101… |
… | …101000000000111011001011 |
3 | 222021022120020210111011220111 |
4 | 231203031311220000323023 |
5 | 202224220202022324042 |
6 | 1550023151132335151 |
7 | 60124343003322334 |
oct | 5543156550007313 |
9 | 867276223434814 |
10 | 200332133011147 |
11 | 58917420489505 |
12 | 1a5758620144b7 |
13 | 87a231535b147 |
14 | 37681ac5b128b |
15 | 1826172760517 |
hex | b63375a00ecb |
200332133011147 has 2 divisors, whose sum is σ = 200332133011148. Its totient is φ = 200332133011146.
The previous prime is 200332133011097. The next prime is 200332133011189. The reversal of 200332133011147 is 741110331233002.
200332133011147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200332133011147 - 27 = 200332133011019 is a prime.
It is not a weakly prime, because it can be changed into another prime (200332133011547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100166066505573 + 100166066505574.
It is an arithmetic number, because the mean of its divisors is an integer number (100166066505574).
Almost surely, 2200332133011147 is an apocalyptic number.
200332133011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
200332133011147 is an equidigital number, since it uses as much as digits as its factorization.
200332133011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 200332133011147 its reverse (741110331233002), we get a palindrome (941442464244149).
The spelling of 200332133011147 in words is "two hundred trillion, three hundred thirty-two billion, one hundred thirty-three million, eleven thousand, one hundred forty-seven".
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