Base | Representation |
---|---|
bin | 10010101010000100… |
… | …110011001010101001 |
3 | 1220201011002202020111 |
4 | 102222010303022221 |
5 | 312012003112212 |
6 | 13111514054321 |
7 | 1306304564335 |
oct | 225204631251 |
9 | 56634082214 |
10 | 20033254057 |
11 | 8550282313 |
12 | 3a7111a3a1 |
13 | 1b7354baab |
14 | d808a07c5 |
15 | 7c3b38ea7 |
hex | 4aa1332a9 |
20033254057 has 2 divisors, whose sum is σ = 20033254058. Its totient is φ = 20033254056.
The previous prime is 20033253979. The next prime is 20033254069. The reversal of 20033254057 is 75045233002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11281838656 + 8751415401 = 106216^2 + 93549^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20033254057 is a prime.
It is a super-2 number, since 2×200332540572 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20033254097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016627028 + 10016627029.
It is an arithmetic number, because the mean of its divisors is an integer number (10016627029).
Almost surely, 220033254057 is an apocalyptic number.
It is an amenable number.
20033254057 is a deficient number, since it is larger than the sum of its proper divisors (1).
20033254057 is an equidigital number, since it uses as much as digits as its factorization.
20033254057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 31.
Adding to 20033254057 its reverse (75045233002), we get a palindrome (95078487059).
The spelling of 20033254057 in words is "twenty billion, thirty-three million, two hundred fifty-four thousand, fifty-seven".
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