Base | Representation |
---|---|
bin | 1001000111000011010011… |
… | …10011010101000010011011 |
3 | 2121221011222020101110022121 |
4 | 10203201221303111002123 |
5 | 10111212103122003424 |
6 | 110335133005402111 |
7 | 4135241603603344 |
oct | 443415163250233 |
9 | 77834866343277 |
10 | 20033502531739 |
11 | 64241849a7aa4 |
12 | 22b6763569337 |
13 | b241c71c0908 |
14 | 4d38ab9230cb |
15 | 24b1b621bee4 |
hex | 123869cd509b |
20033502531739 has 2 divisors, whose sum is σ = 20033502531740. Its totient is φ = 20033502531738.
The previous prime is 20033502531631. The next prime is 20033502531769. The reversal of 20033502531739 is 93713520533002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20033502531739 - 237 = 19896063578267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20033502531695 and 20033502531704.
It is not a weakly prime, because it can be changed into another prime (20033502531769) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016751265869 + 10016751265870.
It is an arithmetic number, because the mean of its divisors is an integer number (10016751265870).
Almost surely, 220033502531739 is an apocalyptic number.
20033502531739 is a deficient number, since it is larger than the sum of its proper divisors (1).
20033502531739 is an equidigital number, since it uses as much as digits as its factorization.
20033502531739 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 510300, while the sum is 43.
The spelling of 20033502531739 in words is "twenty trillion, thirty-three billion, five hundred two million, five hundred thirty-one thousand, seven hundred thirty-nine".
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