Base | Representation |
---|---|
bin | 11101001001110101010… |
… | …100101000110001110010 |
3 | 21002112012000000120000221 |
4 | 131021311110220301302 |
5 | 230311002303312424 |
6 | 4132205422003254 |
7 | 264512456260315 |
oct | 35116524506162 |
9 | 7075160016027 |
10 | 2003423104114 |
11 | 702713127653 |
12 | 28433a41652a |
13 | 116bca7b9473 |
14 | 6cd7535297c |
15 | 371a879a9e4 |
hex | 1d275528c72 |
2003423104114 has 8 divisors (see below), whose sum is σ = 3005210511360. Its totient is φ = 1001686266996.
The previous prime is 2003423104087. The next prime is 2003423104121. The reversal of 2003423104114 is 4114013243002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12543334 + ... + 12702049.
It is an arithmetic number, because the mean of its divisors is an integer number (375651313920).
Almost surely, 22003423104114 is an apocalyptic number.
2003423104114 is a deficient number, since it is larger than the sum of its proper divisors (1001787407246).
2003423104114 is a wasteful number, since it uses less digits than its factorization.
2003423104114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25285064.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2003423104114 its reverse (4114013243002), we get a palindrome (6117436347116).
The spelling of 2003423104114 in words is "two trillion, three billion, four hundred twenty-three million, one hundred four thousand, one hundred fourteen".
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