Base | Representation |
---|---|
bin | 1001000111000100110100… |
… | …01010111011100001011111 |
3 | 2121221021001210100120212121 |
4 | 10203202122022323201133 |
5 | 10111220233342300210 |
6 | 110335345314443411 |
7 | 4135300656306151 |
oct | 443423212734137 |
9 | 77837053316777 |
10 | 20034314025055 |
11 | 6424560a78a30 |
12 | 22b694b293567 |
13 | b242c6368c85 |
14 | 4d3947600ad1 |
15 | 24b2125b46da |
hex | 12389a2bb85f |
20034314025055 has 16 divisors (see below), whose sum is σ = 26228224976544. Its totient is φ = 14569584302080.
The previous prime is 20034314025043. The next prime is 20034314025109. The reversal of 20034314025055 is 55052041343002.
It is not a de Polignac number, because 20034314025055 - 25 = 20034314025023 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20034314025055.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9343762 + ... + 11286031.
It is an arithmetic number, because the mean of its divisors is an integer number (1639264061034).
Almost surely, 220034314025055 is an apocalyptic number.
20034314025055 is a deficient number, since it is larger than the sum of its proper divisors (6193910951489).
20034314025055 is a wasteful number, since it uses less digits than its factorization.
20034314025055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20647466.
The product of its (nonzero) digits is 72000, while the sum is 34.
Adding to 20034314025055 its reverse (55052041343002), we get a palindrome (75086355368057).
The spelling of 20034314025055 in words is "twenty trillion, thirty-four billion, three hundred fourteen million, twenty-five thousand, fifty-five".
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