Base | Representation |
---|---|
bin | 101101100011011001000110… |
… | …110010011001000000101011 |
3 | 222021100201111000001210001211 |
4 | 231203121012302121000223 |
5 | 202224414441404311404 |
6 | 1550032511502053551 |
7 | 60125251560032425 |
oct | 5543310662310053 |
9 | 867321430053054 |
10 | 200344232103979 |
11 | 5892156a071a87 |
12 | 1a578079b7a2b7 |
13 | 87a34c2ba9582 |
14 | 37689d9425815 |
15 | 182662ea56b04 |
hex | b63646c9902b |
200344232103979 has 2 divisors, whose sum is σ = 200344232103980. Its totient is φ = 200344232103978.
The previous prime is 200344232103959. The next prime is 200344232103991. The reversal of 200344232103979 is 979301232443002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200344232103979 - 25 = 200344232103947 is a prime.
It is a super-2 number, since 2×2003442321039792 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200344232103959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100172116051989 + 100172116051990.
It is an arithmetic number, because the mean of its divisors is an integer number (100172116051990).
Almost surely, 2200344232103979 is an apocalyptic number.
200344232103979 is a deficient number, since it is larger than the sum of its proper divisors (1).
200344232103979 is an equidigital number, since it uses as much as digits as its factorization.
200344232103979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 49.
The spelling of 200344232103979 in words is "two hundred trillion, three hundred forty-four billion, two hundred thirty-two million, one hundred three thousand, nine hundred seventy-nine".
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