Base | Representation |
---|---|
bin | 1001000111000101101001… |
… | …11000010110101110010011 |
3 | 2121221022020000120012210021 |
4 | 10203202310320112232103 |
5 | 10111222143101444223 |
6 | 110335502003244311 |
7 | 4135315040236312 |
oct | 443426470265623 |
9 | 77838200505707 |
10 | 20034762140563 |
11 | 6424770a17825 |
12 | 22b6a55379697 |
13 | b24368155c91 |
14 | 4d398ad2c279 |
15 | 24b23bace65d |
hex | 1238b4e16b93 |
20034762140563 has 2 divisors, whose sum is σ = 20034762140564. Its totient is φ = 20034762140562.
The previous prime is 20034762140537. The next prime is 20034762140579. The reversal of 20034762140563 is 36504126743002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034762140563 - 25 = 20034762140531 is a prime.
It is not a weakly prime, because it can be changed into another prime (20034762140963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017381070281 + 10017381070282.
It is an arithmetic number, because the mean of its divisors is an integer number (10017381070282).
Almost surely, 220034762140563 is an apocalyptic number.
20034762140563 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034762140563 is an equidigital number, since it uses as much as digits as its factorization.
20034762140563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 43.
Adding to 20034762140563 its reverse (36504126743002), we get a palindrome (56538888883565).
The spelling of 20034762140563 in words is "twenty trillion, thirty-four billion, seven hundred sixty-two million, one hundred forty thousand, five hundred sixty-three".
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