Base | Representation |
---|---|
bin | 10010101010001011… |
… | …000100111000010101 |
3 | 1220201021012100022222 |
4 | 102222023010320111 |
5 | 312012413240402 |
6 | 13112013232125 |
7 | 1306324556435 |
oct | 225213047025 |
9 | 56637170288 |
10 | 20034899477 |
11 | 85511a656a |
12 | 3a71792645 |
13 | 1b739a6a08 |
14 | d80bac2c5 |
15 | 7c3d617a2 |
hex | 4aa2c4e15 |
20034899477 has 4 divisors (see below), whose sum is σ = 20038001100. Its totient is φ = 20031797856.
The previous prime is 20034899459. The next prime is 20034899491. The reversal of 20034899477 is 77499843002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13364747236 + 6670152241 = 115606^2 + 81671^2 .
It is a cyclic number.
It is not a de Polignac number, because 20034899477 - 214 = 20034883093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20034899497) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1541102 + ... + 1554047.
It is an arithmetic number, because the mean of its divisors is an integer number (5009500275).
Almost surely, 220034899477 is an apocalyptic number.
It is an amenable number.
20034899477 is a deficient number, since it is larger than the sum of its proper divisors (3101623).
20034899477 is an equidigital number, since it uses as much as digits as its factorization.
20034899477 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3101622.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 20034899477 in words is "twenty billion, thirty-four million, eight hundred ninety-nine thousand, four hundred seventy-seven".
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