Base | Representation |
---|---|
bin | 11101001010010111100… |
… | …101101000010011000110 |
3 | 21002120200001202110220102 |
4 | 131022113211220103012 |
5 | 230313141440441232 |
6 | 4132342435404102 |
7 | 264532636543643 |
oct | 35122745502306 |
9 | 7076601673812 |
10 | 2003997983942 |
11 | 702988688349 |
12 | 28447aa53632 |
13 | 116c8c92b246 |
14 | 6cdcb83adca |
15 | 371ddea5662 |
hex | 1d2979684c6 |
2003997983942 has 4 divisors (see below), whose sum is σ = 3005996975916. Its totient is φ = 1001998991970.
The previous prime is 2003997983941. The next prime is 2003997983971. The reversal of 2003997983942 is 2493897993002.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×20039979839423 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003997983941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500999495984 + ... + 500999495987.
It is an arithmetic number, because the mean of its divisors is an integer number (751499243979).
Almost surely, 22003997983942 is an apocalyptic number.
2003997983942 is a deficient number, since it is larger than the sum of its proper divisors (1001998991974).
2003997983942 is a wasteful number, since it uses less digits than its factorization.
2003997983942 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1001998991973.
The product of its (nonzero) digits is 52907904, while the sum is 65.
The spelling of 2003997983942 in words is "two trillion, three billion, nine hundred ninety-seven million, nine hundred eighty-three thousand, nine hundred forty-two".
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