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2003997983942 = 21001998991971
BaseRepresentation
bin11101001010010111100…
…101101000010011000110
321002120200001202110220102
4131022113211220103012
5230313141440441232
64132342435404102
7264532636543643
oct35122745502306
97076601673812
102003997983942
11702988688349
1228447aa53632
13116c8c92b246
146cdcb83adca
15371ddea5662
hex1d2979684c6

2003997983942 has 4 divisors (see below), whose sum is σ = 3005996975916. Its totient is φ = 1001998991970.

The previous prime is 2003997983941. The next prime is 2003997983971. The reversal of 2003997983942 is 2493897993002.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×20039979839423 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003997983941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500999495984 + ... + 500999495987.

It is an arithmetic number, because the mean of its divisors is an integer number (751499243979).

Almost surely, 22003997983942 is an apocalyptic number.

2003997983942 is a deficient number, since it is larger than the sum of its proper divisors (1001998991974).

2003997983942 is a wasteful number, since it uses less digits than its factorization.

2003997983942 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001998991973.

The product of its (nonzero) digits is 52907904, while the sum is 65.

The spelling of 2003997983942 in words is "two trillion, three billion, nine hundred ninety-seven million, nine hundred eighty-three thousand, nine hundred forty-two".

Divisors: 1 2 1001998991971 2003997983942