Base | Representation |
---|---|
bin | 1001000111001111101000… |
… | …01110111010001010100011 |
3 | 2121221211001102021220100211 |
4 | 10203213310032322022203 |
5 | 10111314131204003203 |
6 | 110342145400354551 |
7 | 4135564566201412 |
oct | 443476416721243 |
9 | 77854042256324 |
10 | 20040119984803 |
11 | 6426a70317476 |
12 | 22b7aab775a57 |
13 | b24a10186309 |
14 | 4d3d3873d479 |
15 | 24b45216dc6d |
hex | 1239f43ba2a3 |
20040119984803 has 2 divisors, whose sum is σ = 20040119984804. Its totient is φ = 20040119984802.
The previous prime is 20040119984723. The next prime is 20040119984813. The reversal of 20040119984803 is 30848991104002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20040119984803 - 217 = 20040119853731 is a prime.
It is not a weakly prime, because it can be changed into another prime (20040119984813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10020059992401 + 10020059992402.
It is an arithmetic number, because the mean of its divisors is an integer number (10020059992402).
Almost surely, 220040119984803 is an apocalyptic number.
20040119984803 is a deficient number, since it is larger than the sum of its proper divisors (1).
20040119984803 is an equidigital number, since it uses as much as digits as its factorization.
20040119984803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 49.
The spelling of 20040119984803 in words is "twenty trillion, forty billion, one hundred nineteen million, nine hundred eighty-four thousand, eight hundred three".
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