Base | Representation |
---|---|
bin | 1001000111010010010000… |
… | …10001111000011110010011 |
3 | 2121221221200200120122210110 |
4 | 10203221020101320132103 |
5 | 10111330023143103301 |
6 | 110342541331132403 |
7 | 4135644540436110 |
oct | 443511021703623 |
9 | 77857620518713 |
10 | 20041530050451 |
11 | 6427624260688 |
12 | 22b8223a44103 |
13 | b24ba634a4a0 |
14 | 4d402db11907 |
15 | 24b4d5d510d6 |
hex | 123a48478793 |
20041530050451 has 64 divisors (see below), whose sum is σ = 34031557324800. Its totient is φ = 10204186761216.
The previous prime is 20041530050449. The next prime is 20041530050459. The reversal of 20041530050451 is 15405003514002.
It is not a de Polignac number, because 20041530050451 - 21 = 20041530050449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20041530050459) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 30463750 + ... + 31114676.
It is an arithmetic number, because the mean of its divisors is an integer number (531743083200).
Almost surely, 220041530050451 is an apocalyptic number.
20041530050451 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
20041530050451 is a deficient number, since it is larger than the sum of its proper divisors (13990027274349).
20041530050451 is a wasteful number, since it uses less digits than its factorization.
20041530050451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 654868.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 20041530050451 its reverse (15405003514002), we get a palindrome (35446533564453).
The spelling of 20041530050451 in words is "twenty trillion, forty-one billion, five hundred thirty million, fifty thousand, four hundred fifty-one".
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