Base | Representation |
---|---|
bin | 1011101010101000010… |
… | …1110001000101101101 |
3 | 201011022202121022122122 |
4 | 2322222011301011231 |
5 | 11240431031243000 |
6 | 232023405522325 |
7 | 20323435013513 |
oct | 2725205610555 |
9 | 634282538578 |
10 | 200422134125 |
11 | 77aa9084884 |
12 | 32a14b733a5 |
13 | 15b90910395 |
14 | 99b41a84b3 |
15 | 533055b085 |
hex | 2eaa17116d |
200422134125 has 16 divisors (see below), whose sum is σ = 263291396160. Its totient is φ = 151898878800.
The previous prime is 200422134119. The next prime is 200422134127. The reversal of 200422134125 is 521431224002.
200422134125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-200422134125 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200422134094 and 200422134103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200422134127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42191759 + ... + 42196508.
It is an arithmetic number, because the mean of its divisors is an integer number (16455712260).
Almost surely, 2200422134125 is an apocalyptic number.
200422134125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
200422134125 is a deficient number, since it is larger than the sum of its proper divisors (62869262035).
200422134125 is an equidigital number, since it uses as much as digits as its factorization.
200422134125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84388301 (or 84388291 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 200422134125 its reverse (521431224002), we get a palindrome (721853358127).
The spelling of 200422134125 in words is "two hundred billion, four hundred twenty-two million, one hundred thirty-four thousand, one hundred twenty-five".
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