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20042343133 = 71282286523
BaseRepresentation
bin10010101010100111…
…011110001011011101
31220201210012112002221
4102222213132023131
5312021314440013
613112440545341
71306445051161
oct225247361335
956653175087
1020042343133
11855542004a
123a74182251
131b753b1b47
14d81b88ca1
157c483208d
hex4aa9de2dd

20042343133 has 4 divisors (see below), whose sum is σ = 20324629728. Its totient is φ = 19760056540.

The previous prime is 20042343109. The next prime is 20042343143. The reversal of 20042343133 is 33134324002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20042343133 - 217 = 20042212061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20042343098 and 20042343107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20042343143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141143191 + ... + 141143332.

It is an arithmetic number, because the mean of its divisors is an integer number (5081157432).

Almost surely, 220042343133 is an apocalyptic number.

It is an amenable number.

20042343133 is a deficient number, since it is larger than the sum of its proper divisors (282286595).

20042343133 is an equidigital number, since it uses as much as digits as its factorization.

20042343133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 282286594.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 20042343133 its reverse (33134324002), we get a palindrome (53176667135).

The spelling of 20042343133 in words is "twenty billion, forty-two million, three hundred forty-three thousand, one hundred thirty-three".

Divisors: 1 71 282286523 20042343133