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20042422450433 is a prime number
BaseRepresentation
bin1001000111010011111010…
…11110000111100100000001
32121222000222212210021102122
410203221331132013210001
510111333340121403213
6110343210050254025
74136005624632245
oct443517536074401
977860885707378
1020042422450433
116427a41a71a29
1222b8432887315
13b24cb91b2806
144d40b6450425
1524b53937ad08
hex123a7d787901

20042422450433 has 2 divisors, whose sum is σ = 20042422450434. Its totient is φ = 20042422450432.

The previous prime is 20042422450423. The next prime is 20042422450447. The reversal of 20042422450433 is 33405422424002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19951525024369 + 90897426064 = 4466713^2 + 301492^2 .

It is a cyclic number.

It is not a de Polignac number, because 20042422450433 - 24 = 20042422450417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20042422450393 and 20042422450402.

It is not a weakly prime, because it can be changed into another prime (20042422450403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10021211225216 + 10021211225217.

It is an arithmetic number, because the mean of its divisors is an integer number (10021211225217).

Almost surely, 220042422450433 is an apocalyptic number.

It is an amenable number.

20042422450433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20042422450433 is an equidigital number, since it uses as much as digits as its factorization.

20042422450433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 184320, while the sum is 35.

Adding to 20042422450433 its reverse (33405422424002), we get a palindrome (53447844874435).

The spelling of 20042422450433 in words is "twenty trillion, forty-two billion, four hundred twenty-two million, four hundred fifty thousand, four hundred thirty-three".