Base | Representation |
---|---|
bin | 11101001010101100101… |
… | …000101010010011111001 |
3 | 21002121120200012122021121 |
4 | 131022230220222103321 |
5 | 230314402340201103 |
6 | 4132441452105241 |
7 | 264544455150163 |
oct | 35125450522371 |
9 | 7077520178247 |
10 | 2004351100153 |
11 | 703049a40826 |
12 | 284559165221 |
13 | 117017b3594c |
14 | 6d0226b9933 |
15 | 3720eea76bd |
hex | 1d2aca2a4f9 |
2004351100153 has 4 divisors (see below), whose sum is σ = 2004355755108. Its totient is φ = 2004346445200.
The previous prime is 2004351100139. The next prime is 2004351100187. The reversal of 2004351100153 is 3510011534002.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 729908796409 + 1274442303744 = 854347^2 + 1128912^2 .
It is a cyclic number.
It is not a de Polignac number, because 2004351100153 - 25 = 2004351100121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2004351104153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1607326 + ... + 2567527.
It is an arithmetic number, because the mean of its divisors is an integer number (501088938777).
Almost surely, 22004351100153 is an apocalyptic number.
It is an amenable number.
2004351100153 is a deficient number, since it is larger than the sum of its proper divisors (4654955).
2004351100153 is an equidigital number, since it uses as much as digits as its factorization.
2004351100153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4654954.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 2004351100153 its reverse (3510011534002), we get a palindrome (5514362634155).
The spelling of 2004351100153 in words is "two trillion, four billion, three hundred fifty-one million, one hundred thousand, one hundred fifty-three".
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