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2004411140503 = 15671279139209
BaseRepresentation
bin11101001010110000001…
…101101100100110010111
321002121201212012000011021
4131022300031230212113
5230320013222444003
64132451435022011
7264546114403012
oct35126015544627
97077655160137
102004411140503
1170307a919a52
1228457529a907
131170273c8095
146d02a668379
15372153b72bd
hex1d2b036c997

2004411140503 has 4 divisors (see below), whose sum is σ = 2005690281280. Its totient is φ = 2003131999728.

The previous prime is 2004411140471. The next prime is 2004411140513. The reversal of 2004411140503 is 3050411144002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2004411140503 - 25 = 2004411140471 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2004411140513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 639568038 + ... + 639571171.

It is an arithmetic number, because the mean of its divisors is an integer number (501422570320).

Almost surely, 22004411140503 is an apocalyptic number.

2004411140503 is a deficient number, since it is larger than the sum of its proper divisors (1279140777).

2004411140503 is a wasteful number, since it uses less digits than its factorization.

2004411140503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1279140776.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 2004411140503 its reverse (3050411144002), we get a palindrome (5054822284505).

The spelling of 2004411140503 in words is "two trillion, four billion, four hundred eleven million, one hundred forty thousand, five hundred three".

Divisors: 1 1567 1279139209 2004411140503