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200441124731 is a prime number
BaseRepresentation
bin1011101010101100111…
…0001101011101111011
3201011101002100010212102
42322223032031131323
511241000411442411
6232025324534015
720324055306641
oct2725316153573
9634332303772
10200441124731
11780088757a1
1232a1b3b130b
1315b9482c223
1499b690d191
15533205cd3b
hex2eab38d77b

200441124731 has 2 divisors, whose sum is σ = 200441124732. Its totient is φ = 200441124730.

The previous prime is 200441124703. The next prime is 200441124757. The reversal of 200441124731 is 137421144002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200441124731 is a prime.

It is a super-2 number, since 2×2004411247312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200441124694 and 200441124703.

It is not a weakly prime, because it can be changed into another prime (200441124931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100220562365 + 100220562366.

It is an arithmetic number, because the mean of its divisors is an integer number (100220562366).

Almost surely, 2200441124731 is an apocalyptic number.

200441124731 is a deficient number, since it is larger than the sum of its proper divisors (1).

200441124731 is an equidigital number, since it uses as much as digits as its factorization.

200441124731 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 200441124731 its reverse (137421144002), we get a palindrome (337862268733).

The spelling of 200441124731 in words is "two hundred billion, four hundred forty-one million, one hundred twenty-four thousand, seven hundred thirty-one".