Base | Representation |
---|---|
bin | 1001000111011000101110… |
… | …01110111010010110001011 |
3 | 2121222021122122221212101011 |
4 | 10203230113032322112023 |
5 | 10111404131022433103 |
6 | 110344314042304351 |
7 | 4136126561025061 |
oct | 443542716722613 |
9 | 77867578855334 |
10 | 20045002155403 |
11 | 6429046165505 |
12 | 22b8a327b80b7 |
13 | b2530a79ac64 |
14 | 4d427cccc031 |
15 | 24b63aa9cd6d |
hex | 123b173ba58b |
20045002155403 has 2 divisors, whose sum is σ = 20045002155404. Its totient is φ = 20045002155402.
The previous prime is 20045002155359. The next prime is 20045002155419. The reversal of 20045002155403 is 30455120054002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20045002155403 - 237 = 19907563201931 is a prime.
It is a super-2 number, since 2×200450021554032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20045002155473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10022501077701 + 10022501077702.
It is an arithmetic number, because the mean of its divisors is an integer number (10022501077702).
Almost surely, 220045002155403 is an apocalyptic number.
20045002155403 is a deficient number, since it is larger than the sum of its proper divisors (1).
20045002155403 is an equidigital number, since it uses as much as digits as its factorization.
20045002155403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 31.
The spelling of 20045002155403 in words is "twenty trillion, forty-five billion, two million, one hundred fifty-five thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •