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20045559913 is a prime number
BaseRepresentation
bin10010101010110011…
…101111100001101001
31220202000020221200221
4102222303233201221
5312023130404123
613113033530041
71306514306431
oct225263574151
956660227627
1020045559913
118557217945
123a75273921
131b75c6a072
14d823852c1
157c4c6a25d
hex4aacef869

20045559913 has 2 divisors, whose sum is σ = 20045559914. Its totient is φ = 20045559912.

The previous prime is 20045559907. The next prime is 20045559971. The reversal of 20045559913 is 31995554002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19911185449 + 134374464 = 141107^2 + 11592^2 .

It is a cyclic number.

It is not a de Polignac number, because 20045559913 - 25 = 20045559881 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20045559913.

It is not a weakly prime, because it can be changed into another prime (20045559973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10022779956 + 10022779957.

It is an arithmetic number, because the mean of its divisors is an integer number (10022779957).

Almost surely, 220045559913 is an apocalyptic number.

It is an amenable number.

20045559913 is a deficient number, since it is larger than the sum of its proper divisors (1).

20045559913 is an equidigital number, since it uses as much as digits as its factorization.

20045559913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243000, while the sum is 43.

The spelling of 20045559913 in words is "twenty billion, forty-five million, five hundred fifty-nine thousand, nine hundred thirteen".