Base | Representation |
---|---|
bin | 1001000111011101011110… |
… | …11011101001010011000011 |
3 | 2121222112020121202211101120 |
4 | 10203232233123221103003 |
5 | 10111424343220132100 |
6 | 110345415300203323 |
7 | 4136250055143165 |
oct | 443565733512303 |
9 | 77875217684346 |
10 | 20047555630275 |
11 | 642a136572a18 |
12 | 22b9425999543 |
13 | b25626801334 |
14 | 4d444209c935 |
15 | 24b739d3d0a0 |
hex | 123baf6e94c3 |
20047555630275 has 24 divisors (see below), whose sum is σ = 33146048040960. Its totient is φ = 10691785777440.
The previous prime is 20047555630253. The next prime is 20047555630279. The reversal of 20047555630275 is 57203655574002.
It is not a de Polignac number, because 20047555630275 - 25 = 20047555630243 is a prime.
It is a super-3 number, since 3×200475556302753 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (20047555630279) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 285354 + ... + 6338496.
It is an arithmetic number, because the mean of its divisors is an integer number (1381085335040).
Almost surely, 220047555630275 is an apocalyptic number.
20047555630275 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
20047555630275 is a deficient number, since it is larger than the sum of its proper divisors (13098492410685).
20047555630275 is a wasteful number, since it uses less digits than its factorization.
20047555630275 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6097315 (or 6097310 counting only the distinct ones).
The product of its (nonzero) digits is 8820000, while the sum is 51.
The spelling of 20047555630275 in words is "twenty trillion, forty-seven billion, five hundred fifty-five million, six hundred thirty thousand, two hundred seventy-five".
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