Base | Representation |
---|---|
bin | 11101001011011011010… |
… | …000100100010001101101 |
3 | 21002200121012002011202201 |
4 | 131023123100210101231 |
5 | 230323003112010013 |
6 | 4133051233421501 |
7 | 264603033642406 |
oct | 35133320442155 |
9 | 7080535064681 |
10 | 2005133313133 |
11 | 703410532a35 |
12 | 28473710a891 |
13 | 117110bcb772 |
14 | 6d0985349ad |
15 | 372589b93dd |
hex | 1d2db42446d |
2005133313133 has 4 divisors (see below), whose sum is σ = 2005174600128. Its totient is φ = 2005092026140.
The previous prime is 2005133313101. The next prime is 2005133313137. The reversal of 2005133313133 is 3313133315002.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2005133313133 - 25 = 2005133313101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2005133313137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20570563 + ... + 20667808.
It is an arithmetic number, because the mean of its divisors is an integer number (501293650032).
Almost surely, 22005133313133 is an apocalyptic number.
It is an amenable number.
2005133313133 is a deficient number, since it is larger than the sum of its proper divisors (41286995).
2005133313133 is an equidigital number, since it uses as much as digits as its factorization.
2005133313133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41286994.
The product of its (nonzero) digits is 7290, while the sum is 28.
Adding to 2005133313133 its reverse (3313133315002), we get a palindrome (5318266628135).
The spelling of 2005133313133 in words is "two trillion, five billion, one hundred thirty-three million, three hundred thirteen thousand, one hundred thirty-three".
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