Base | Representation |
---|---|
bin | 11101001011011011011… |
… | …000001100110010000111 |
3 | 21002200121022211211111221 |
4 | 131023123120030302013 |
5 | 230323004120022210 |
6 | 4133051344341211 |
7 | 264603056645116 |
oct | 35133330146207 |
9 | 7080538754457 |
10 | 2005135314055 |
11 | 70341167a295 |
12 | 284737914807 |
13 | 11711144c443 |
14 | 6d0988d5c7d |
15 | 37258c621da |
hex | 1d2db60cc87 |
2005135314055 has 4 divisors (see below), whose sum is σ = 2406162376872. Its totient is φ = 1604108251240.
The previous prime is 2005135314019. The next prime is 2005135314067. The reversal of 2005135314055 is 5504135315002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2005135314055 - 211 = 2005135312007 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2005135314055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200513531401 + ... + 200513531410.
It is an arithmetic number, because the mean of its divisors is an integer number (601540594218).
Almost surely, 22005135314055 is an apocalyptic number.
2005135314055 is a deficient number, since it is larger than the sum of its proper divisors (401027062817).
2005135314055 is an equidigital number, since it uses as much as digits as its factorization.
2005135314055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 401027062816.
The product of its (nonzero) digits is 45000, while the sum is 34.
The spelling of 2005135314055 in words is "two trillion, five billion, one hundred thirty-five million, three hundred fourteen thousand, fifty-five".
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