Base | Representation |
---|---|
bin | 11101001011011111110… |
… | …101100001100001011001 |
3 | 21002200210112120212022122 |
4 | 131023133311201201121 |
5 | 230323132242010131 |
6 | 4133103015431025 |
7 | 264604655465165 |
oct | 35133765414131 |
9 | 7080715525278 |
10 | 2005210110041 |
11 | 70344a916656 |
12 | 284758985475 |
13 | 117123aa9c18 |
14 | 6d0a4805ca5 |
15 | 372605d8d7b |
hex | 1d2dfd61859 |
2005210110041 has 2 divisors, whose sum is σ = 2005210110042. Its totient is φ = 2005210110040.
The previous prime is 2005210110037. The next prime is 2005210110073. The reversal of 2005210110041 is 1400110125002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1948525642816 + 56684467225 = 1395896^2 + 238085^2 .
It is a cyclic number.
It is not a de Polignac number, because 2005210110041 - 22 = 2005210110037 is a prime.
It is not a weakly prime, because it can be changed into another prime (2005210110091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002605055020 + 1002605055021.
It is an arithmetic number, because the mean of its divisors is an integer number (1002605055021).
Almost surely, 22005210110041 is an apocalyptic number.
It is an amenable number.
2005210110041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005210110041 is an equidigital number, since it uses as much as digits as its factorization.
2005210110041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 2005210110041 its reverse (1400110125002), we get a palindrome (3405320235043).
The spelling of 2005210110041 in words is "two trillion, five billion, two hundred ten million, one hundred ten thousand, forty-one".
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