Base | Representation |
---|---|
bin | 11101001011101100111… |
… | …101010010101011101001 |
3 | 21002201100212211010212111 |
4 | 131023230331102223221 |
5 | 230324110121001332 |
6 | 4133140522042321 |
7 | 264613300604242 |
oct | 35135475225351 |
9 | 7081325733774 |
10 | 2005430250217 |
11 | 703553105189 |
12 | 2847ba6493a1 |
13 | 11715a596394 |
14 | 6d0c5b4bcc9 |
15 | 37274ac0947 |
hex | 1d2ecf52ae9 |
2005430250217 has 2 divisors, whose sum is σ = 2005430250218. Its totient is φ = 2005430250216.
The previous prime is 2005430250191. The next prime is 2005430250281. The reversal of 2005430250217 is 7120520345002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1466705077776 + 538725172441 = 1211076^2 + 733979^2 .
It is a cyclic number.
It is not a de Polignac number, because 2005430250217 - 235 = 1971070511849 is a prime.
It is not a weakly prime, because it can be changed into another prime (2005430650217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002715125108 + 1002715125109.
It is an arithmetic number, because the mean of its divisors is an integer number (1002715125109).
Almost surely, 22005430250217 is an apocalyptic number.
It is an amenable number.
2005430250217 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005430250217 is an equidigital number, since it uses as much as digits as its factorization.
2005430250217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 31.
Adding to 2005430250217 its reverse (7120520345002), we get a palindrome (9125950595219).
The spelling of 2005430250217 in words is "two trillion, five billion, four hundred thirty million, two hundred fifty thousand, two hundred seventeen".
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