Base | Representation |
---|---|
bin | 1001001001001000100010… |
… | …01010111101111101000111 |
3 | 2122012000121002221100100121 |
4 | 10210210101022331331013 |
5 | 10113400100140003310 |
6 | 110432042343322411 |
7 | 4143353246214511 |
oct | 444442112757507 |
9 | 78160532840317 |
10 | 20105030000455 |
11 | 645154a330a04 |
12 | 23085a5a50407 |
13 | b2ab85c272ba |
14 | 4d713534cbb1 |
15 | 24cea09a10da |
hex | 1249112bdf47 |
20105030000455 has 8 divisors (see below), whose sum is σ = 24126506940672. Its totient is φ = 16083710040288.
The previous prime is 20105030000371. The next prime is 20105030000459. The reversal of 20105030000455 is 55400003050102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20105030000455 - 219 = 20105029476167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20105030000459) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38963064 + ... + 39475693.
It is an arithmetic number, because the mean of its divisors is an integer number (3015813367584).
Almost surely, 220105030000455 is an apocalyptic number.
20105030000455 is a deficient number, since it is larger than the sum of its proper divisors (4021476940217).
20105030000455 is an equidigital number, since it uses as much as digits as its factorization.
20105030000455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78490025.
The product of its (nonzero) digits is 3000, while the sum is 25.
Adding to 20105030000455 its reverse (55400003050102), we get a palindrome (75505033050557).
The spelling of 20105030000455 in words is "twenty trillion, one hundred five billion, thirty million, four hundred fifty-five", and thus it is an aban number.
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