20110002000113 has 2 divisors, whose sum is σ = 20110002000114. Its totient is φ = 20110002000112.

The previous prime is 20110002000001. The next prime is 20110002000181. The reversal of 20110002000113 is 31100020001102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18555960521569 + 1554041478544 = 4307663^2 + 1246612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20110002000113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20110002000094 and 20110002000103.

It is not a weakly prime, because it can be changed into another prime (20110008000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055001000056 + 10055001000057.

It is an arithmetic number, because the mean of its divisors is an integer number (10055001000057).

Almost surely, 2^{20110002000113} is an apocalyptic number.

It is an amenable number.

20110002000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20110002000113 is an equidigital number, since it uses as much as digits as its factorization.

20110002000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 20110002000113 its reverse (31100020001102), we get a palindrome (51210022001215).

The spelling of 20110002000113 in words is "twenty trillion, one hundred ten billion, two million, one hundred thirteen", and thus it is an aban number.