Base | Representation |
---|---|
bin | 1011101101001010000… |
… | …1001010011010110011 |
3 | 201020002000220000120001 |
4 | 2323102201022122303 |
5 | 11243323200420103 |
6 | 232214555330431 |
7 | 20346312143053 |
oct | 2732241123263 |
9 | 636060800501 |
10 | 201100404403 |
11 | 78316a32328 |
12 | 32b84150a17 |
13 | 15c6b2b1c42 |
14 | 9a3a2c7563 |
15 | 536ed8a01d |
hex | 2ed284a6b3 |
201100404403 has 2 divisors, whose sum is σ = 201100404404. Its totient is φ = 201100404402.
The previous prime is 201100404383. The next prime is 201100404419. The reversal of 201100404403 is 304404001102.
201100404403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201100404403 is a prime.
It is not a weakly prime, because it can be changed into another prime (201100408403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100550202201 + 100550202202.
It is an arithmetic number, because the mean of its divisors is an integer number (100550202202).
Almost surely, 2201100404403 is an apocalyptic number.
201100404403 is a deficient number, since it is larger than the sum of its proper divisors (1).
201100404403 is an equidigital number, since it uses as much as digits as its factorization.
201100404403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 201100404403 its reverse (304404001102), we get a palindrome (505504405505).
The spelling of 201100404403 in words is "two hundred one billion, one hundred million, four hundred four thousand, four hundred three".
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